Integrand size = 13, antiderivative size = 47 \[ \int (A+B x) (d+e x)^m \, dx=-\frac {(B d-A e) (d+e x)^{1+m}}{e^2 (1+m)}+\frac {B (d+e x)^{2+m}}{e^2 (2+m)} \]
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Time = 0.02 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {45} \[ \int (A+B x) (d+e x)^m \, dx=\frac {B (d+e x)^{m+2}}{e^2 (m+2)}-\frac {(B d-A e) (d+e x)^{m+1}}{e^2 (m+1)} \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {(-B d+A e) (d+e x)^m}{e}+\frac {B (d+e x)^{1+m}}{e}\right ) \, dx \\ & = -\frac {(B d-A e) (d+e x)^{1+m}}{e^2 (1+m)}+\frac {B (d+e x)^{2+m}}{e^2 (2+m)} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.87 \[ \int (A+B x) (d+e x)^m \, dx=\frac {(d+e x)^{1+m} (-B d+A e (2+m)+B e (1+m) x)}{e^2 (1+m) (2+m)} \]
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Time = 1.51 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.98
method | result | size |
gosper | \(\frac {\left (e x +d \right )^{1+m} \left (B e m x +A e m +e B x +2 A e -B d \right )}{e^{2} \left (m^{2}+3 m +2\right )}\) | \(46\) |
risch | \(\frac {\left (x^{2} B \,e^{2} m +A \,e^{2} m x +B d e m x +x^{2} B \,e^{2}+A d e m +2 A \,e^{2} x +2 A d e -B \,d^{2}\right ) \left (e x +d \right )^{m}}{e^{2} \left (2+m \right ) \left (1+m \right )}\) | \(76\) |
norman | \(\frac {B \,x^{2} {\mathrm e}^{m \ln \left (e x +d \right )}}{2+m}+\frac {d \left (A e m +2 A e -B d \right ) {\mathrm e}^{m \ln \left (e x +d \right )}}{e^{2} \left (m^{2}+3 m +2\right )}+\frac {\left (A e m +B d m +2 A e \right ) x \,{\mathrm e}^{m \ln \left (e x +d \right )}}{e \left (m^{2}+3 m +2\right )}\) | \(95\) |
parallelrisch | \(\frac {B \,x^{2} \left (e x +d \right )^{m} d \,e^{2} m +A x \left (e x +d \right )^{m} d \,e^{2} m +B \,x^{2} \left (e x +d \right )^{m} d \,e^{2}+B x \left (e x +d \right )^{m} d^{2} e m +2 A x \left (e x +d \right )^{m} d \,e^{2}+A \left (e x +d \right )^{m} d^{2} e m +2 A \left (e x +d \right )^{m} d^{2} e -B \left (e x +d \right )^{m} d^{3}}{\left (2+m \right ) d \left (1+m \right ) e^{2}}\) | \(138\) |
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Time = 0.25 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.77 \[ \int (A+B x) (d+e x)^m \, dx=\frac {{\left (A d e m - B d^{2} + 2 \, A d e + {\left (B e^{2} m + B e^{2}\right )} x^{2} + {\left (2 \, A e^{2} + {\left (B d e + A e^{2}\right )} m\right )} x\right )} {\left (e x + d\right )}^{m}}{e^{2} m^{2} + 3 \, e^{2} m + 2 \, e^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 377 vs. \(2 (37) = 74\).
Time = 0.38 (sec) , antiderivative size = 377, normalized size of antiderivative = 8.02 \[ \int (A+B x) (d+e x)^m \, dx=\begin {cases} d^{m} \left (A x + \frac {B x^{2}}{2}\right ) & \text {for}\: e = 0 \\- \frac {A e}{d e^{2} + e^{3} x} + \frac {B d \log {\left (\frac {d}{e} + x \right )}}{d e^{2} + e^{3} x} + \frac {B d}{d e^{2} + e^{3} x} + \frac {B e x \log {\left (\frac {d}{e} + x \right )}}{d e^{2} + e^{3} x} & \text {for}\: m = -2 \\\frac {A \log {\left (\frac {d}{e} + x \right )}}{e} - \frac {B d \log {\left (\frac {d}{e} + x \right )}}{e^{2}} + \frac {B x}{e} & \text {for}\: m = -1 \\\frac {A d e m \left (d + e x\right )^{m}}{e^{2} m^{2} + 3 e^{2} m + 2 e^{2}} + \frac {2 A d e \left (d + e x\right )^{m}}{e^{2} m^{2} + 3 e^{2} m + 2 e^{2}} + \frac {A e^{2} m x \left (d + e x\right )^{m}}{e^{2} m^{2} + 3 e^{2} m + 2 e^{2}} + \frac {2 A e^{2} x \left (d + e x\right )^{m}}{e^{2} m^{2} + 3 e^{2} m + 2 e^{2}} - \frac {B d^{2} \left (d + e x\right )^{m}}{e^{2} m^{2} + 3 e^{2} m + 2 e^{2}} + \frac {B d e m x \left (d + e x\right )^{m}}{e^{2} m^{2} + 3 e^{2} m + 2 e^{2}} + \frac {B e^{2} m x^{2} \left (d + e x\right )^{m}}{e^{2} m^{2} + 3 e^{2} m + 2 e^{2}} + \frac {B e^{2} x^{2} \left (d + e x\right )^{m}}{e^{2} m^{2} + 3 e^{2} m + 2 e^{2}} & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.34 \[ \int (A+B x) (d+e x)^m \, dx=\frac {{\left (e^{2} {\left (m + 1\right )} x^{2} + d e m x - d^{2}\right )} {\left (e x + d\right )}^{m} B}{{\left (m^{2} + 3 \, m + 2\right )} e^{2}} + \frac {{\left (e x + d\right )}^{m + 1} A}{e {\left (m + 1\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 132 vs. \(2 (47) = 94\).
Time = 0.28 (sec) , antiderivative size = 132, normalized size of antiderivative = 2.81 \[ \int (A+B x) (d+e x)^m \, dx=\frac {{\left (e x + d\right )}^{m} B e^{2} m x^{2} + {\left (e x + d\right )}^{m} B d e m x + {\left (e x + d\right )}^{m} A e^{2} m x + {\left (e x + d\right )}^{m} B e^{2} x^{2} + {\left (e x + d\right )}^{m} A d e m + 2 \, {\left (e x + d\right )}^{m} A e^{2} x - {\left (e x + d\right )}^{m} B d^{2} + 2 \, {\left (e x + d\right )}^{m} A d e}{e^{2} m^{2} + 3 \, e^{2} m + 2 \, e^{2}} \]
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Time = 3.22 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.87 \[ \int (A+B x) (d+e x)^m \, dx={\left (d+e\,x\right )}^m\,\left (\frac {x\,\left (2\,A\,e^2+A\,e^2\,m+B\,d\,e\,m\right )}{e^2\,\left (m^2+3\,m+2\right )}+\frac {B\,x^2\,\left (m+1\right )}{m^2+3\,m+2}+\frac {d\,\left (2\,A\,e-B\,d+A\,e\,m\right )}{e^2\,\left (m^2+3\,m+2\right )}\right ) \]
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